函数f(x)=2x−5f(x)=\dfrac{2}{x - 5}f(x)=x−52的定义域是(). (A)(−∞,5)(-\infty,5)(−∞,5) (B)(5,+∞)(5, +\infty)(5,+∞) (C)(−∞,5)∪(5,+∞)(-\infty,5)\cup(5, +\infty)(−∞,5)∪(5,+∞) (D)[5,+∞)[5, +\infty)[5,+∞)
limx→2(1x−2−4x2−4)=\lim\limits_{x \to 2}(\dfrac{1}{x - 2} - \dfrac{4}{x^2 - 4}) =x→2lim(x−21−x2−44)=(). (A)12\dfrac{1}{2}21 (B)14\dfrac{1}{4}41 (C)−14-\dfrac{1}{4}−41 (D)∞\infty∞
设f(x)=ax3+4x2x−2f(x)=\dfrac{ax^3 + 4x^2}{x - 2}f(x)=x−2ax3+4x2有可去间断点x=2x = 2x=2,则a=a =a=(). (A)−1-1−1 (B)222 (C)eee (D)000
已知f′(5)=−4f'(5) = - 4f′(5)=−4,则极限limh→0f(5)−f(5+h)2h=\lim\limits_{h \to 0}\dfrac{f(5) - f(5 + h)}{2h} =h→0lim2hf(5)−f(5+h)=(). (A)000 (B)222 (C)−2-2−2 (D)−4-4−4
设y=x2lnxy = x^2\ln xy=x2lnx,则y′=y' =y′=(). (A)2xlnx+2x2x\ln x + 2x2xlnx+2x (B)2xlnx+x2x\ln x + x2xlnx+x (C)2lnx+12\ln x + 12lnx+1 (D)2lnx+32\ln x + 32lnx+3
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