设y=y(x)y = y(x)y=y(x)由参数方程{x=2et+1y=t3−3t\begin{cases}x = 2e^{t}+1\\y=t^{3}-3t\end{cases}{x=2et+1y=t3−3t所确定,求dydx\dfrac{dy}{dx}dxdy.
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