设函数y=y(x)y = y(x)y=y(x)由参数方程{x=1ty=arctant\begin{cases}x=\dfrac{1}{t}\\y = \arctan t\end{cases}⎩⎨⎧x=t1y=arctant所确定,求曲线y=y(x)y = y(x)y=y(x)在t=1t = 1t=1对应点处的法线方程.
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