已知limx→1f(x)=1\lim\limits_{x \to 1} f(x) = 1x→1limf(x)=1，limx→1g(x)=2\lim\limits_{x \to 1} g(x) = 2x→1limg(x)=2，则limx→1[f(x)+g(x)]=\lim\limits_{x \to 1} [f(x) + g(x)] =x→1lim[f(x)+g(x)]=（ ）.
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