若f(x)=13sinx+axf(x)=\dfrac{1}{3}\sin x + axf(x)=31sinx+ax在x=0x = 0x=0处有极值,则a=a =a=( ).
(A)−13-\dfrac{1}{3}−31
(B)13\dfrac{1}{3}31
(C)1
(D)−1-1−1
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