∫022y−y2dy=\int_{0}^{2} \sqrt{2y - y^2} dy =∫022y−y2dy=（ ）.
（A）π3\dfrac{\pi}{3}3π
（B）1
（C）π2\dfrac{\pi}{2}2π
（D）π4\dfrac{\pi}{4}4π
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