点(0,1)(0,1)(0,1)是曲线y=x3+bx2+cy = x^3 + bx^2 + cy=x3+bx2+c的拐点，则（ ）.
（A）b=0,c=1b = 0, c = 1b=0,c=1
（B）b=−1,c=0b = -1, c = 0b=−1,c=0
（C）b=1,c=1b = 1, c = 1b=1,c=1
（D）b=−1,c=1b = -1, c = 1b=−1,c=1
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