设参数方程为{x=1+sin2θy=2sinθ+3\begin{cases}x = 1+\sin2\theta\\y = 2\sin\theta + 3\end{cases}{x=1+sin2θy=2sinθ+3,θ\thetaθ为参数,求dydx∣θ=0\left.\dfrac{dy}{dx}\right|_{\theta = 0}dxdyθ=0.
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