设f(x)f(x)f(x)是连续的函数,且∫01f(x)dx=1\int_{0}^{1}f(x)dx = 1∫01f(x)dx=1,则∫10f(x)dx=−1\int_{1}^{0}f(x)dx=-1∫10f(x)dx=−1.( )
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