设f(x)={a+x2,x≤01xsin1x,x>0f(x)=\begin{cases}a + x^{2},&x\leq0\\\dfrac{1}{x}\sin\dfrac{1}{x},&x > 0\end{cases}f(x)=⎩⎨⎧a+x2,x1sinx1,x≤0x>0在x=0x = 0x=0处连续,求aaa的值.
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