∫0π2−x2dx=\int_{0}^{\pi}\sqrt{2 - x^{2}}dx =∫0π2−x2dx=( ).
(A)12π\dfrac{1}{2}\pi21π
(B)π\piπ
(C)32π\dfrac{3}{2}\pi23π
(D)2π2\pi2π
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