设函数f(x),g(x)f(x),g(x)f(x),g(x)均可微,且同为某函数的原函数,f(0)=2,g(0)=0f(0)=2,g(0)=0f(0)=2,g(0)=0,则f(x)−g(x)=f(x)-g(x)=f(x)−g(x)=( ).
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