已知limx→π2f(x)\lim\limits_{x \to \frac{\pi}{2}} f(x)x→2πlimf(x)存在,且f(x)=2x+4limx→π2f(x)f(x)=2x + 4\lim\limits_{x \to \frac{\pi}{2}} f(x)f(x)=2x+4x→2πlimf(x),则limx→π2f(x)=\lim\limits_{x \to \frac{\pi}{2}} f(x)=x→2πlimf(x)=( ).
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