设函数f(x)f(x)f(x)在点x=2x = 2x=2处连续,且limx→2f(x)x−2=4\lim\limits_{x \to 2} \dfrac{f(x)}{x - 2}=4x→2limx−2f(x)=4,则f(2)=f(2) =f(2)=( ).
(A)−4-4−4
(B)000
(C)14\dfrac{1}{4}41
(D)444
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