设函数y=f(3x+2)y = f(3x + 2)y=f(3x+2)的定义域为[1,3][1,3][1,3],则函数f(x)f(x)f(x)的定义域为( ).
(A)[−13,13][-\dfrac{1}{3},\dfrac{1}{3}][−31,31]
(B)[5,11][5,11][5,11]
(C)(−13,13)(-\dfrac{1}{3},\dfrac{1}{3})(−31,31)
(D)(5,11)(5,11)(5,11)
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