设函数f(x)f(x)f(x),g(x)g(x)g(x)均可微,且同为某函数的原函数,f(0)=2f(0) = 2f(0)=2,g(0)=0g(0) = 0g(0)=0,则f(x)−g(x)=f(x) - g(x) =f(x)−g(x)=( ).
Copyright ©