∫019−x2dx=\int_{0}^{1} \sqrt{9 - x^2}dx=∫019−x2dx=( ).
(A)3π4\dfrac{3\pi}{4}43π
(B)9π4\dfrac{9\pi}{4}49π
(C)π4\dfrac{\pi}{4}4π
(D)9π2\dfrac{9\pi}{2}29π
Copyright ©