limn→∞[11⋅2+12⋅3+⋯+1n(n+1)]\lim\limits_{n\to\infty}\left[\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\cdots+\dfrac{1}{n(n + 1)}\right]n→∞lim[1⋅21+2⋅31+⋯+n(n+1)1]=( ).
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