设f(x)={a+x2,x≤0xsin1x,x>0f(x)=\begin{cases}a + x^2, & x \leq 0\\x\sin\dfrac{1}{x}, & x > 0\end{cases}f(x)=⎩⎨⎧a+x2,xsinx1,x≤0x>0,在x=0x = 0x=0处连续,求aaa的值.
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