设函数f(x)f(x)f(x)在x=1x = 1x=1处连续,且limx→1f(x)=6\lim\limits_{x \to 1}f(x)=6x→1limf(x)=6,则f(1)=f(1)=f(1)=( ).
(A)1
(B)0
(C)6
(D)−6-6−6
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