设函数f(x)f(x)f(x)在x=2x = 2x=2处可导,且limx→0f(2+x)−f(2)2x=2\lim\limits_{x \to 0}\dfrac{f(2 + x) - f(2)}{2x}=2x→0lim2xf(2+x)−f(2)=2,则f′(2)=f^\prime(2)=f′(2)=( ).
(A)222
(B)111
(C)444
(D)−2-2−2
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