f(x)=ln(x2+3)f(x)=\ln(x^2 + 3)f(x)=ln(x2+3),则f′(1)=f'(1) =f′(1)=( ).
(A)14\dfrac{1}{4}41
(B)−14-\dfrac{1}{4}−41
(C)12\dfrac{1}{2}21
(D)−12-\dfrac{1}{2}−21
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