设函数f(x)f(x)f(x)，g(x)g(x)g(x)均可微，且同为某函数的原函数，f(0)=2f(0) = 2f(0)=2，g(0)=0g(0) = 0g(0)=0，则f(x)−g(x)=f(x) - g(x) =f(x)−g(x)=（ ）.
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