ddx∫−1xcos2tdt=cos2x\dfrac{d}{dx}\int_{-1}^{x}\cos^{2}tdt=\cos^{2}xdxd∫−1xcos2tdt=cos2x.( )
若函数在一点处极限存在,则在该点处一定连续.( )
已知y=f(3−x)y = f(3 - x)y=f(3−x),f(x)f(x)f(x)可导,则dy=f′(3−x)dxdy = f'(3 - x)dxdy=f′(3−x)dx.( )
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