已知函数f(x)=x(x+1)(x+1)2f(x)=x(x + 1)(x + 1)^{2}f(x)=x(x+1)(x+1)2,则f(x)f(x)f(x)的单调递增区间是( )
(A)(−∞,−1)(-\infty,-1)(−∞,−1)
(B)(−1,−12)(-1,-\dfrac{1}{2})(−1,−21)
(C)(−14,∞)(-\dfrac{1}{4},\infty)(−41,∞)
(D)[−1,12][-1,\dfrac{1}{2}][−1,21]
设f(x)=2x+3x−2f(x)=2^{x}+3^{x}-2f(x)=2x+3x−2,当x→0x\to0x→0时,有( ).
(A)f(x)f(x)f(x)与xxx等价无穷小
(B)f(x)f(x)f(x)与xxx同阶但非等价无穷小
(C)f(x)f(x)f(x)是比xxx高阶的无穷小