已知f(x)=2x+13ln(1+6x)f(x)=\sqrt{2x}+\dfrac{1}{3}\ln(1 + 6x)f(x)=2x+31ln(1+6x),求f′(x)f'(x)f′(x)。
设y=y(x)y = y(x)y=y(x)是由{x=costy=t+sin2t\begin{cases}x=\cos t\\y = t+\sin2t\end{cases}{x=costy=t+sin2t确定的函数,求dydx∣t=−π2\left.\dfrac{dy}{dx}\right|_{t = -\frac{\pi}{2}}dxdyt=−2π。
已知函数f(x)={1,∣x∣>10,∣x∣≤1f(x)=\begin{cases}1, & \vert x \vert > 1 \\ 0, & \vert x \vert \leq 1\end{cases}f(x)={1,0,∣x∣>1∣x∣≤1,则f[f(2)]=0f[f(2)] = 0f[f(2)]=0.( )
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