y=2x3+x+4xy = \dfrac{2x^3+\sqrt{x}+4}{x}y=x2x3+x+4,则y′(1)=y'(1)=y′(1)=( ).
曲线y=x3+5x−2y = x^3 + 5x - 2y=x3+5x−2的拐点是( ).
∫−11tanxdx=\int_{-1}^{1}\tan x dx =∫−11tanxdx=( ).
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