已知∫1xf(t)dt=x3−1\int_{1}^{x} f(t)dt=x^3 - 1∫1xf(t)dt=x3−1，则f(2)=f(2)=f(2)=（ ）.
limx→8(16x2−64−1x−8)\lim\limits_{x \to 8} (\dfrac{16}{x^2 - 64}-\dfrac{1}{x - 8})x→8lim(x2−6416−x−81).
limx→+∞ln(1+ex)x\lim\limits_{x \to +\infty} \dfrac{\ln(1 + e^x)}{x}x→+∞limxln(1+ex).
Copyright ©
