limx→0ln(cosx)x2\lim\limits_{x \to 0} \dfrac{\ln(\cos x)}{x^2}x→0limx2ln(cosx).
已知函数y=sin2x−2x+1y = \sin2x-\sqrt{2x + 1}y=sin2x−2x+1,求dydydy.
已知y=y(x)y = y(x)y=y(x)由方程y3+y2=2xy^{3}+y^{2}=2xy3+y2=2x所确定,求dydx\dfrac{dy}{dx}dxdy.
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