limx→0(1−x)1x=\lim\limits_{x \to 0}(1 - x)^{\frac{1}{x}}=x→0lim(1−x)x1=( ).
y=2x3+x+4xy = \dfrac{2x^3+\sqrt{x}+4}{x}y=x2x3+x+4,则y′(1)=y'(1)=y′(1)=( ).
曲线y=x3+5x−2y = x^3 + 5x - 2y=x3+5x−2的拐点是( ).
Copyright ©