设fn=n−fn−2f_n = n - f_{n - 2}fn=n−fn−2,当n=0n = 0n=0或111时,fn=2f_n = 2fn=2,输出当n=7n = 7n=7时fnf_nfn的值。请补全代码。
#include<stdio.h> int f(int n){ int fn; if(①) return(2); fn = n - f(n - 2); return ②; } void main( ){ int x; x = f(7); printf("%d\n", ③); }
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