函数y=2x2−lnxy = 2x^2 - \ln xy=2x2−lnx的单调递减区间为( ).
(A)(0,12](0,\dfrac{1}{2}](0,21]
(B)(−∞,12](-\infty,\dfrac{1}{2}](−∞,21]
(C)[12,+∞)[\dfrac{1}{2},+\infty)[21,+∞)
(D)[−12,12][-\dfrac{1}{2},\dfrac{1}{2}][−21,21]
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