已知∫f(x)dx=e2x+C\int f(x)dx = e^{2x}+C∫f(x)dx=e2x+C,∫g(x)dx=2x+C\int g(x)dx=\sqrt{2x}+C∫g(x)dx=2x+C,则∫[f(x)+g(x)]dx=\int [f(x)+g(x)]dx =∫[f(x)+g(x)]dx=( ).
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