设函数f(x)=∫0x(e−t+t2)dtf(x)=\int_{0}^{x}(e^{-t}+t^2)dtf(x)=∫0x(e−t+t2)dt,则f′(x)=−e−x+2xf'(x)=-e^{-x}+2xf′(x)=−e−x+2x.( )
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