已知连续函数f(x)f(x)f(x)在区间(−1,1)(-1,1)(−1,1)内的任意一点x(x≠0)x (x \neq 0)x(x=0)处都有f(x)<f(0)f(x) < f(0)f(x)<f(0),则f(0)f(0)f(0)为f(x)f(x)f(x)在(−1,1)(-1,1)(−1,1)内的极大值.( )
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